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# Swan-Song -- Math Rules

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This is the extant film converted to 48fps using FC Pro.

The clip consists of 7 frames.

133-134 = 1frame span.   134-135 = 1 frame span

If you remove 5 frames between the first and last, the position of the limo will match the extant film.

From extant z135, continue on, removing 1/2 the frames until the next cluster needs to be removed.

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1 hour ago, Chris Davidson said:

If you remove 5 frames between the first and last, the position of the limo will match the extant film.

first and last?  133 and 135?   you talking about that jag to the left in the unstabilized version

that sentence really doesn't help clarify it buddy...

At about 1 foot per frame,  2 frames divided by .25 = 8 frames at 48 fps

to 134 to 135 at 18.3 = to 133.1 - 133.2 - 133.3 - 134 - 134.1 - 134.2 -  134.3 - 135 at 48 Ffps

remove half (4 frames) leaving 4      133.1, 133.2, 134.1, 134.2
remove half (2 frames) leaving 2      133.3,              134.3

2 frames left, 5 removed... from a 48 fps film...

but I still don't understand what you mean by "the position of the limo will match the extant film"

when and where?

Edited by David Josephs
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You do not start removing every other frame until after the first 5 of the original 48 are excised.

In other words,

Start and keep z133,  remove the next 5 consecutive frames from the 48fps version.

Keep z135, then, remove the next frame and this starts the 1/2 pass removal process.

5 frames removed from a 48fps version = a frame jump of 2.16-2.4ft = a 2 frame distance traveled in the extant film.

Those 5 frames are the only part of that span (z133-z135) which will be removed.

There will be no more removal of frames, via the other passes, within that span.

Sequence:

Keep1 Remove(23456) Keep 7 9 11 13 15 17 .........

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On 3/28/2018 at 9:06 AM, David Josephs said:

incredible Chris...

Thanks David,

Two more for you:

(18/48) x (2) x (1.2) x (1/.9) = whole frames

(1 - .11111) x 18 = frame rate

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18 hours ago, Chris Davidson said:

Thanks David,

Two more for you:

(18/48) x (2) x (1.2) x (1/.9) = whole frames

(1 - .11111) x 18 = frame rate

18 X 2 = 36 X 1.2 =  43.2 X 1.1111 = 48 / 48 = 1

(1-.11111) = .888889 X 18 = 16 frames per second (1 of the 2 settings for speed on the B&H)  the other was 48fps

If the film was not altered or taken at 48fps it would have been taken at 16fps

What happens to all the calcs when you revert back to the normal camera speed - and why was 18.3 so much more important to use than 16?

First big reason was the incline of Elm with a rise/run of 1'/18.3'

16/18.3 = .8743

From the first splice, 133, to 313... 180 frames @18.3 frames drops to 157 frames at 16 fps.  z313 - 157 frames = z156, the location of the 2nd splice and exactly half the frames.

180 frames minus 157 frames = 23 frames @ ~1 foot per frame is the length of the limo

z156 - z133 = 23 frames = length of the limo

===========

{thinking out loud}

486 frames @ 18.3 = 425 frames @ 16.    61 frame diff
353 frames (486-133) = 309 frames @ 16   42 frame diff...

42 frames would be the distance between 313 and the final shot per the SS...

Edited by David Josephs
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2 hours ago, David Josephs said:

18 X 2 = 36 X 1.2 =  43.2 X 1.1111 = 48 / 48 = 1

(1-.11111) = .888889 X 18 = 16 frames per second (1 of the 2 settings for speed on the B&H)  the other was 48fps

Both results are correct.

Since I've been listing splits, this might be a better way to look at the top equation:

18/48 = .375 x 2 (remove 1/2)  = .75 x 1.2 (remove 1/6) = .9 x 1.11111 = 1

They never got back to 1 whole frame.

Something like this:

They are short 353 x 1.11111 = 392.22 - 353 = 39.22 frames.

Either spread out over the entire 353 frame span, or specific areas.

I would hope there are some "unaccounted for" frames, how else would the limo severely slow down near the two headshots 13.1(hybrid) frames apart, without severely slowing down on the extant films.

1296 = 486 x (48/18)
354.6666666 = 133 x (48/18)
941.33333 = (1296 - 354.66666)
470.666666 = (941.3333 / 2)

470.666666 - 16.6666% = (1/2 x 1/3) =
392.22 - 353 =
39.22 Remaining

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DB Thomas Acoustical:

5.7sec between labeled shots 2/3

.7 seconds between labeled shots 3/4

5.7 x 2.3 (18.3 - 16) = 13.11 hybrid frames

13.11 / 18.3 = .716seconds

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On ‎3‎/‎29‎/‎2018 at 4:00 PM, Chris Davidson said:

470.666666 - 16.6666% = (1/2 x 1/3) =
392.22 - 353 =
39.22 Remaining

This is AFTER 133  (486 - 133 = 353)

Q: 39.22 frames at 18.3 fps, not 48... right?

39.22 / 18.3 = 2.143 seconds....  & also equals 39.22 * either (48/18.3) =  103 whole frames or  (48/18) = 105 whole frames at 48fps

Let's look at the likely candidates for removal...

z154 - z158...  while it appears that z157's top is spliced into z156's bottom...  JFK's head turn in 1 frame seems impossible

z207 (WEST location fro a shot) thru z212  -  1 of 2 shots removed

z207 to z208 on CE884 is 2.24 feet which = 28mph....  it was not possible for the limo to travel that distance in 1 frame so 208 was changed to 210 in CE884 to bring the spped down under 10mph

On CE585 we can see the faint writing stating that Shot #1 at frame 207/8 was a bit farther up Elm...   So while JFK and JC appear to be hit nearly simultaneously... there was a fraction of a second separating the 2 shots...  Many feel JFK was hit, possibly twice between 190 and 223...

Z302 - 303 is another example of an extreme head turn and the fact that the image is relatively uniform in focus despite - supposedly - the limo or the camera was moving...

And again at 314-316

and again at 350 - right where the shot by the stairs occurs

Mr. LIEBELER - You also testified that you were standing perhaps no more than 15 feet away when the President was hit in the head and that you are absolutely certain that there were no shots fired after the President was hit in the head?
Mr. ALTGENS - Yes, sir; that's correct.

.....There was flesh particles that flew out of the side of his head in my direction from where I was standing, so much so that it indicated to me that the shot came out of the left side of his head.

Edited by David Josephs
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Chris, (and David)- this is the interview of Lee Bowers , who had a bird's eye view of the assassin(s) behind grassy knoll fence. Does this correlate to your findings?

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13 hours ago, David Josephs said:

Let's look at the likely candidates for removal...

z154 - z158...  while it appears that z157's top is spliced into z156's bottom...  JFK's head turn in 1 frame seems impossible

Most definitely agree.

Sometimes it's easier to slo-mo the scene.

That's when the obvious jumps will appear, even when using Groden's non missing frames.

Edited by Chris Davidson
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2 hours ago, Chuck Schwartz said:

Chris, (and David)- this is the interview of Lee Bowers , who had a bird's eye view of the assassin(s) behind grassy knoll fence. Does this correlate to your findings?

Chuck,

Two shots close together. Yes

How many others????

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To ponder:

If the shooters were connected via COLLINS RADIOS... the "Fire" command would allow 2-3 shooters to fire within a split second of each other...

.... also, the area where the Tramps walk past Lansdale....  same area as you have a shooter for the 2nd z313 shot...

Except it appears too large and that he shouldn't be all black

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On 3/29/2018 at 4:00 PM, Chris Davidson said:

Both results are correct.

Since I've been listing splits, this might be a better way to look at the top equation:

18/48 = .375 x 2 (remove 1/2)  = .75 x 1.2 (remove 1/6) = .9 x 1.11111 = 1

They never got back to 1 whole frame.

Something like this:

They are short 353 x 1.11111 = 392.22 - 353 = 39.22 frames.

Either spread out over the entire 353 frame span, or specific areas.

I would hope there are some "unaccounted for" frames, how else would the limo severely slow down near the two headshots 13.1(hybrid) frames apart, without severely slowing down on the extant films.

1296 = 486 x (48/18)
354.6666666 = 133 x (48/18)
941.33333 = (1296 - 354.66666)
470.666666 = (941.3333 / 2)

470.666666 - 16.6666% = (1/2 x 1/3) =
392.22 - 353 =
39.22 Remaining

Whole Frames Conversion:

353/16 = 22.0625

353/18 = 19.6111

2.4514 sec x 16fps = 39.22 frames

P.S. Since there are two different conversions which yield the same missing frame count, can I call them hybrid frames?

Added on edit: 353/18.3 = 19.2896 sec

22.0625 - 19.2896 = 2.7729 sec x 18.3 = 50.74 frames/ft

2.7729sec x 16.0 = 44.36 frames/ft

Edited by Chris Davidson
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On 3/26/2018 at 8:34 PM, Chris Davidson said:

Let's use Myers 108% manipulation to sync his distance difference with CE884:

79.2ft x 1.08% = 85.536ft

85.536ft - 79.2ft = 6.336ft

6.336ft - .9ft = 5.436ft difference

Now refer to the distance per frame traveled from CE884 z161-z166 = .18ft per frame traveled

The WC difference comes in the span of z133-z161 = 30.2ft (Station# 299- 329.2)

30.2ft  x .18ft = 5.436ft

How many frames might we be dealing with for that equation:

30.2 /.18 = 167.77

After revamping Towner's filming position, and replotting JFK within the limo from that filming position, the distance JFK travels between the Towner film end and z133 = 5.625ft.

The last 20 frames of Towner has JFK travel 12.5ft.

Working in between the Myers lines to figure out how he would hide this short span of approx 5.625ft.

9.2mph x 1.47 = 13.524ft per sec

Myers has the Z camera frame rate at 18.3 for syncing.

He provides a 15 frame gap between Towner end and Z133. (See the problem forming with only 5.625ft to deal with?)

18.3/15 = 1.22

13.524ft/1.22 = 11.085ft traveled for 15 frames, but we only have 5.625ft to work with.

So let's remedy Myers with what is known to be true:

Using the plotted distance/frame count of Towner 12.5ft/20 frames = .625ft per frame

5.625ft/.625 = 9 frames

A 6 frame difference from the 15 Myers uses.

11.085ft - 5.625ft = 5.46ft difference

12.5ft(last 20 frames of Towner) + 5.46ft difference = 17.96ft

17.96ft / 20 frames = .898ft per frame x 16fps = 14.368ft per sec / 1.47 = 9.77mph

Quite close to his ideal 9.8mph target.

btw, 15frames@ 5.625ft using 18.3frames per sec = 4.668mph

Couple that with the other speed entries. previously provided for z133-z149 = 14.88mph + 4.668mph = 19.54/2 = 9.77mph = match

P.S.

If the difference was 5.49ft, instead of 5.46ft, this would give you the CE884 provided distance for z168-z171 of 3 frames@.9ft converted over 18.3 frames.

And, 5.5ft difference = 12.5ft + 5.5 ft = 18ft/20 frames = .9ft per frame = Shaneyfelt average for z161-z313.

It would also match Myers 9.8mph.

.9ft x 16fps = 14.4ft.per sec / 1.47 = 9.795 mph

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