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# Swan-Song -- Math Rules

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The inch designed building blocks the WC used were:

.875 + 2.665 = 3.54 + 10 + 39.24 = 52.78" = JFK's stated/testimony head height above the street while seated in the limo.

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1 hour ago, Chris Davidson said:

Before the incline, the back hole was .75" above the throat hole.

After the incline, the back hole is below the throat hole by .75 - 1.18 = -.43"

Did you happen to run .43" through a run/rise calc at 7"?

Then deduct 3.13° for the reverse Elm St slope.

3.52° - 3.13° = .39° = 0deg 23.4minutes

And, match it back to a CE884 frame # from the bridge handrail(overpass).

z210-z222 = 2/12 = .1666min per frame

1.4min/ .1666min per frame = 8.4 frames

z210 + 8.4 frames = z218.4

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8 hours ago, Chris Davidson said:

Button the shirt, along with what's in the red square.

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12 hours ago, Chris Davidson said:

Button the shirt, along with what's in the red square.

If only Arlen Specter had .gif's available to him...

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On 8/22/2019 at 1:53 PM, Chris Davidson said:

The inch designed building blocks the WC used were:

.875 + 2.665 = 3.54 + 10 + 39.24 = 52.78" = JFK's stated/testimony head height above the street while seated in the limo.

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On 8/23/2019 at 12:54 AM, Chris Davidson said:

Button the shirt, along with what's in the red square.

Chris, the deniers will just say "the front of the shirt must have  bunched up".😁

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Ray,

That's fine. I'll just continue on, to where a/the back shot came from.

Mr. SIMMONS. Yes; we did. We placed three targets, which were head and shoulder silhouettes, at distances of 175 feet, 240 feet, and 265 feet, and these distances are slant ranges from the window ledge of a tower which is about 30 feet high. We used three firers in an attempt to obtain hits on all three targets within as short a time interval as possible.

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Next, refer back to these two posts:

1.625" - 1.18" = .445" back hole higher than throat hole.

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On 8/27/2019 at 4:14 PM, Chris Davidson said:

Mr. SIMMONS. Yes; we did. We placed three targets, which were head and shoulder silhouettes, at distances of 175 feet, 240 feet, and 265 feet, and these distances are slant ranges from the window ledge of a tower which is about 30 feet high. We used three firers in an attempt to obtain hits on all three targets within as short a time interval as possible.

Height and angle.

Distance next.

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1" = 10ft

Base measurement match: See previous post.

The LOS from elev. 423.07 = Shot #1 labeled on the SS/FBI Dec-1963 plat.

Richard Sprague used z226 back to the Dal-Tex building as his LOS, I just shortened it to elev 423.07(approx z218) and ran his LOS back to the Dal-Tex.

It intersects approx 30ft from the Dal-Tex corner.

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1 hour ago, Chris Davidson said:

Height and angle.

Distance next.

I arrived at the 30ft height this way:

Elev. of Dal-Tex building base = 430.8ft (430.2 + .3 (SniperNest to TSBD Corner)   + .3 (TSBD Corner to Dal-Tex)

Drommer converted back to West: 430.2 - 100.4 = 329.8 + 161.1 = 490.9

2nd floor window sill = 20ft = (approx height of the TSBD 2nd floor)

Elev 450.8 - 423.07(shot#1-SS/FBI Dec-1963 plat) = 27.73ft - 3.27ft(CE884 elev difference) = 24.46ft.

30 - 24.46 = 5.54ft = Rifle barrel end above 2nd floor window sill.

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5.54ft = Rifle barrel end above 2nd floor window sill.

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If you missed the laser dot, I put a red box around it.

The Google view should help with orientation.

Does that look close to 5.54ft above the 2nd floor window ledge?

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21 minutes ago, Chris Davidson said:

5.54ft = Rifle barrel end above 2nd floor window sill.

Were there prospective suspects that fit the location?

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