Chris Davidson Posted May 10, 2016 Author Share Posted May 10, 2016 110ft/18.3 = 6.01ft. elev change. 490.9 - 423.07 = 67.83ft -60.7(window frame sill)- .5(curb height)= 6.63ft elev change. 6.63-6.01 = .62ft elev difference Excerpt from post #118: The slight adjustment between 3.33ft vs 3.27ft is the difference between these elevations = .06ft vertical = .06 x 18.3(1ft vert. per 18.3ft horizontal) = 1.098ft .62ft - .06ft (southerly adjustment see Tom's notes post #118) = .56ft elevation. Link to comment Share on other sites More sharing options...
Chris Davidson Posted May 10, 2016 Author Share Posted May 10, 2016 The .56ft elevation difference coupled with the bogus distance traveled .9ft from z168-z171(CE884 final plat) or z161-z166(CE884 WC final) and added to the difference between (Time/Life determination of shot at extant 207 and FBI/SS determination) 10.2ft farther west down Elm St when converted, equals a total distance of: 10.24ft + .9ft + 10.2ft = 21.34ft This distance equals the exact length of the limo, provided from the WC document in post #3. 256.1" / 12 = 21.34ft Link to comment Share on other sites More sharing options...
Chris Davidson Posted May 11, 2016 Author Share Posted May 11, 2016 (edited) How did I arrive at 1.17ft above the windowsill ledge for surveyed zframe 207? There are a couple of ways to go about this: The easy way is look at survey frame z207, the 92.07 entry (right side of triangle) equals an elevation of 492.07ft The windowsill elevation is 490.9ft, look at the top right of the graphic within this post. Subtract these two and the difference is the rifle height above the windowsill. Or, Since I know the WC used 3.27ft as JFK's head elevation in every single frame surveyed (CE884), I can subtract that from the base elevation of the triangle ( 427.02) and add 3.27ft to the height (65.05) = 427.02 - 3.27 = street elev of 423.75 Subtract this street elev of 423.75 from the windowsill elevation of 490.9ft, since this is to the street. 490.9 - 423.75 = 67.15 and add 3.27ft to the height (65.05) = 68.32 elev And finally, subtract 68.32 - 67.15 = 1.17ft You have to remember there are measurements to the street and measurements to a spot 3.27ft above the street. chris And, with the limo at 21.34ft, this horizontal distance, converted back to a vertical distance elevation in terms of the Elm St. slope (1ft vertical per 18.3ft horizontal) = 21.34/18.3 = 1.166ft In essence, a match for the determination of the (rifle barrel end) elevation, 1.17ft above the windowsill ledge for surveyed zframe 207 Edited May 11, 2016 by Chris Davidson Link to comment Share on other sites More sharing options...
Chris Davidson Posted May 12, 2016 Author Share Posted May 12, 2016 You'll find it in here. I believe this will be the last of Tom's documents I'll be introducing: Referring back to post#72 also, it's obvious that Shaneyfelt is keeping this total distance of 61ft in sync moving down Elm St. 39.66ft + 21.34ft = 61ft Link to comment Share on other sites More sharing options...
Chris Davidson Posted May 14, 2016 Author Share Posted May 14, 2016 SS/FBI shot#1 131.3ft - 110ft = 21.3ft Link to comment Share on other sites More sharing options...
Chris Davidson Posted May 28, 2016 Author Share Posted May 28, 2016 Link to comment Share on other sites More sharing options...
Chris Davidson Posted May 28, 2016 Author Share Posted May 28, 2016 (edited) At 3.27ft above the street, which is what the WC determined JFK's head height to be for all CE884 entries The elevation for Position A is a simple subtraction of 3.27ft = 431.97 - 3.27 = 428.7 elevation = Position A Edited May 28, 2016 by Chris Davidson Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 2, 2016 Author Share Posted June 2, 2016 (edited) See next post. Edited June 2, 2016 by Chris Davidson Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 2, 2016 Author Share Posted June 2, 2016 Distance from (Position A to z168) = 329.2 -278.5 = 50.7ft Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 2, 2016 Author Share Posted June 2, 2016 Let me hypothesize that Position A is the beginning of a frame count sequence. In this case, one that consists of a film shooting at 48fps. The span from Position A to z168 = 168 frames. 168/48fps = 3.5 seconds. Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 2, 2016 Author Share Posted June 2, 2016 Distance from Position A to z168 = 50.7ft 168frames@48fps = 3.5sec Average speed of limo = 50.7ft/3.5sec = 14.485ft per sec 14.485ft per sec / 1.47(1mph) = 9.85mph average Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 2, 2016 Author Share Posted June 2, 2016 (edited) The supplied excerpt is from the Myers' multi sync film project. Position A would land at about Towner frame 136. Added on edit:138 Z168 is between z150 and z175. Myers' average for these two spans is 9.2 and 10.5mph. 9.2 + 10.5mph =19.7/2 = 9.85mph This would equal a match for the previous post. There you go, I just averaged two averages. Edited June 11, 2016 by Chris Davidson Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 2, 2016 Author Share Posted June 2, 2016 (edited) The distance per frame traveled from Position A to z168 (via CE884 data on final WC plat of May1964) treating this as a 48fps equation= 50.7/168 = .301ft per frame. Extend this to the first two entries and the distance traveled between z168-z171= .9ft total or .3ft per frame = a match with the (ft. per frame total) sentence above. Added on edit: 169 frames would be exactly .3ft per frame Edited June 2, 2016 by Chris Davidson Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 5, 2016 Author Share Posted June 5, 2016 Be aware of the differences Shaneyfelt adjusting down the street. 39.66ft - 30.86ft (distance between z313 and Altgens shot) = 8.8ft. Connection between Shaneyfelt and Myers with 8.8ft in the balance. Link to comment Share on other sites More sharing options...
Chris Davidson Posted June 5, 2016 Author Share Posted June 5, 2016 (edited) Myers average speed from z150-175 = 10.5mph Myers average speed from Towner (end) added on edit: to z175 = 9.8mph 10.5 x 2 = 21- 9.8 = 11.2mph = speed traversed from z150-z175 Edited June 11, 2016 by Chris Davidson Link to comment Share on other sites More sharing options...
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