Chris Davidson

I then took the liberty of removing all but the progressive frames from the SS reconstruction video so now we're only dealing with whole frames. You might remember this: https://drive.google.com/file/d/0BwrExtVD005OUmxsRlJLSGhwNE0/view?usp=sharing

It seemed a stretch to believe that Underwood or an associate would have filmed the SS recreation at 18fps since the camera he normally used was most likely a "Bell and Howell Filmo" standard 16mm/24fps camera. The pulldown frames conversion answered that question. Reconstruction shot at 24fps.

The version of the SS recreation film which includes the pulldown footage is here:

I created a gif showing the end result of reverse telecining which shows the conversion of the 3/2 pulldown or 5 frames back to its original 4 progressive. The top part of the gif is the 3/2 pulldown process from the original. The middle part is the reverse telecine result converting it back to its original four progressive frames. Added on edit: I would suggest downloading this and playing it at full view so the pulldown frames are quite obvious to see. https://drive.google.com/file/d/0BwrExtVD005OTjgyVDJSTXlnZUE/view?usp=sharing

There was a suggestion that the SS recreation video was shot at approx 18/18.3fps. If that was indeed true, the pulldown conversion ratio would have been different. 29.97/18 = 1.665/1 ratio = 5/3 pulldown ratio.

After the 3/2 pulldown conversion was completed, the final version specs looks like this.

One aspect of the (added on edit: SS recreation) film I did validate was this: https://en.wikipedia.org/wiki/Three-two_pull_down

Those with a good memory will remember the above frame. Along with a quote I made a few years back: "I am trying to convey that 24fps or some form of it, was used as part or all of the coverup." Didn't quite have the math worked out to fully support this premise at the time.

Way back when, Michael Walton posted a link to a SS recreation video: The most valuable part of this version is missing. No, I'm not insinuating that he knew of the missing segment. Lets fill in a little information about this abbreviated version. The bottom frames were extracted from the video above.

Thanks for the response and the additional information. BTW, I am having NO PROBLEM following your logic. Tom btw, At this time, I look at the film splices in math terms. For instance, 1/2 frames removed first pass. The remaining film is 1/2 full. If I choose to deal with 1/4 frames of the 1/2 remaining in a particular section, I've chosen 1/8 of the frames to deal with for that section. 1/2 eliminated first pass, 1/8 eliminated per section: 4/8 + 1/8 = 5/8 =.625 Something along that line. Hopefully that's easier to visualize for the rest.

You can just exchange the word through for "it". That you fail to disregard not only the "rate x time = distance" formula, but the overlay video as well, speaks volumes. You have contributed absolutely nothing to this topic but the same parroted message. Save everyone the bother and go do something more interesting. The recreation video is waiting in the wings for anyone who needs a challenge.

Jim, It's at the bottom of Page15 in this PDF: https://drive.google.com/file/d/0BwrExtVD005OSEEwdzREeUNha3c/view?usp=sharing

Chris, IIRC, there is a single splice in what is allegedly the ORIGINAL Z-film - is this correct? And if so, then only the copies represent the "assassination movie" in its alleged original form. If this is true, and any ORIGINAL frames are 'missing' at the splice; no alteration of any destroyed frames in the original was required - just alteration or fabrication of the copy... Tom Tom, I don't know what the Original film consists of. I can only refer to the splices in the extant film. The alteration of any destroyed frames (originals that we'll never see) might not have been necessary, but the extant film is not clean enough. imo In terms of the splices and frame count, look back at my overall scenario. Cut the frame total in half to 462.78 (1st pass on Optical printer) 462.78 - 353 = 109.78 to get rid of. 109.78/462.78 = .237 closest whole frame ratio would be 1/4 (surprised) or .25 Difference between .2372 and .25 in terms of 925.56 total frames = .0128 x 925.56 = 11.84 frames or 12 whole frames. Removal of 12 original frames so the math gets back to whole fames. CE884 WC published version z161 Station# 3+29.2 obtained by eliminating 7 frames = z168 = Station# 3+29.2 from CE884 WC final plat version May 1964. Splice at z133, approx z157, splice at approx z208. 12 original frames left to vanish over 3 splices from an original 48fps film. Piece of cake.

You could always take the slow-motion version I supplied previously, count the total number of frames (144) I believe, cut that amount in half, then half it again: Or 144/2 =72/2 = 36 z171- z207 = 36 frames: Refer to overlay video. Amazing!!!

And, if you would like to connect the 3.74mph( actually it's 3.734mph) from the frames prior to the extant 313 headshot back to where it's introduced on CE884 at z168, it looks like this: z168-z186 = 18 frames @ 21.6ft traveled We need to work with a second of time. 18.3/18 = 1.0166… x 21.6ft = 21.96ft per second 21.96/1.47 (1mph) = 14.938mph 3.734 mph remove half the frames, limo travels at 7.468mph 7.468mph remove half the frames, limo travels at 14.936mph It's all math. Why do you think Itek measured every fourth frame at that point in time?

Lets get Itek's opinion back in 1967 I believe. The following is an excerpt from that study: Added on edit: The last 12 frames designation refers to "until the headshot" extant z301-z313. Sorry I didn't specify that in the graphic". If a car is traveling at 3.74 mph on film and you remove 1/2 the frames, the car would appear to travel at 7.48mph. Every fourth frame. "Danger Will Robinson Danger" Itek was very close at 7.6mph.

Give it up. This is an excerpt from Douglas Horn's research: The Two NPIC Zapruder Film Events: "It could have happened this way—consider this: the extant film (that is, the assassination movie, not the Zapruder family scenes present on the two Secret Service copies) in the National Archives (not counting leader) consists of a strip of film 8 feet, 10 inches long (of which only 6 feet, 3 inches contains the imagery of the assassination film, and 2 feet, 7 inches is black, unexposed film with no image showing); then there is a physical splice; then there is a segment of black film." I'll break this down in math terms for everyone: 8ft 10 inches in terms of total frames pertaining to a 16mm/24 frames per sec film. There are 40 frames per physical foot of film using 16mm film. 8ft 10 inches = 8.83ft 8.83ft x 40 frames per foot =353.2 frames The first supposed 132 frames are missing from the Z film. 353.2 + 132 = 485.2 frames Rounded to the next frame = 486 frames = extant Zfilm total The noose is getting tighter.

In the overall equation I first split the original 925+ frames in half. The first step in reducing frames. imo Applying this concept to the span of z171-z207 which is 36 frames @ 41ft traveled 36frames/24fps = 1.5 seconds 41ft / 1.5seconds = 27.33ft per sec = 18.594 mph This matches the limo/lexus overlay video. Added on edit: It also matches the reconstruction video.

Brought this forward just to refresh your memory, as it pertains to the previous videos. I did make a mistake, the speed from z171-z185 = 17.07mph, not 17.18mph z171-z186 = 17.18 mph z185-z186 = 18.67 mph Keep in mind, this is from the orange colored CE884 (it resides on the 1964 WC final plat) which was never released to the public. It is supposed to be based on a 18.3fps movie. We'll see about that in the near future. The concept is simple. When you increase the amount of frames between point A and B, you slow down the limo's speed between that span. For instance: Changing the frame designation for Station 3+29.2 from Z171 to z166 is going to slow down the limo speed. Instead of 17.07mph@ z171-185 (14 frame span), moving it back to z166 now creates a 19 frame span @19.2ft traveled. 19frames/18.3fps = 1.038 19.2ft/1.038 = 18.5ft per sec = 12.58mph. Adding 5 frames just reduced the limo speed from 17.07 to 12.58mph. The 4.49 mph difference over 1 second = 6.6ft that also needs to be accounted for. Look at the next span of frames on CE884 z186-z207 = 20.3ft traveled in 21 frames. Converted using a 18.3fps rate = 21/18.3 = 1.147 20.3ft /1.147 = 17.69ft per sec / 1.47(1mph) = 12.04mph. The overlay movie along with orange CE884 shows the limo traveling between 17.07 and 18.6 mph at this point. It's quite obvious why the frame number assigned to the same Station# was changed. The WC created a uniformed speed to match what you see on film. Unfortunately for them, the uniformed speed should be between 17.07 and 18.68 mph as is seen with the lexus overlay video. Added on edit:

Jeremy, Are you that short-sighted that you do not understand what I just showed with the video overlay? If you don't understand this part, wait until I introduce the FBI sync, talk about someone's belief system being completely destroyed. Maybe another member will step in and explain the significance of the previous few posts to spare you the pain. The extant film process has been recreated. The math works, it's the film that is bogus.

An overall frames equation goes like this: 486-133 = 353 frames 353 x 2.622 = 925.56 925.56/2 = 462.78 462.78 - 353 = 109.78 109.78/462.78 = .237 .237/2 = .1186 .1186 + .5 = .6186 1 - .6186 = .3814 18.3/48 = .38125 The closest whole frame reproduction would have been .625 = 5/8 .625 - .6186 = .0064 .0064 x 925.56 = 5.92 = next whole frame at 6 frames. Need to lose 6 and were at whole frames. Think limo frame span for CE884's z161-166 and z161-168 right in the middle is 6. Not quite 2/3 frame removal (think 28.4fps) but close enough for gubermint work.

Now look at the next span of frames on CE884 z186-z207 = 20.3ft traveled in 21 frames. Converted using a 18.3fps rate = 21/18.3 = 1.147 20.3ft /1.147 = 17.69ft per sec / 1.47(1mph) = 12.04mph. That's a no-no as we know according to the extant film it is traveling at approx 18.68mph though this span. 21 FRAMES TO WORK WITH. 28.4FPS = 28.4/21 = 1.352 X 20.3FT = 27.45FT PER SEC /1.47 = 18.68MPH Please don't assume (some people) that I'm saying someone was shooting a camera at 28.4fps through this sequence. The 28.4 figure comes as a result of a step down process in frame rates. And one only has to compare both CE884's to each other to find out the WC moved the position of Station# 3+29.2 back 7 frames from z168 to z161. Cased closed. But there's more MATH to go.

The reason I filmed my wife moving at 17mph in the lexus video was because of this area in Z. Referring back to the overlaid video, if you look at z207, you'll notice the Lexus front is at the end of the Stemmons sign while the limo is 3 frames faster The video starts at z171 to z207 = 36frames. If the limo was 3 frames faster in that span the ratio would be 36/33 or 1.090909…./1 Its apparent at some point the limo starts moving a little faster than the lexus. If my wife was traveling at approx the same speed as z171-z185 = 17.07mph, then the limo at 1.09/1 faster than that is: 17.07 x 1.09 = 18.60 mph The speed determination for z185-186 = 18.68mph

Brought this forward just to refresh your memory, as it pertains to the previous videos. I did make a mistake, the speed from z171-z185 = 17.07mph, not 17.18mph z171-z186 = 17.18 mph z185-z186 = 18.67 mph Keep in mind, this is from the orange colored CE884 (it resides on the 1964 WC final plat) which was never released to the public. It is supposed to be based on a 18.3fps movie. We'll see about that in the near future.

Next, I took the 2/3 removed frame video, flopped/rotated/ it so the lexus and limo are traveling the approx same direction and overlaid (aligned front of cars) one onto the other starting at z171. To begin with, this is playing at 2fps so you get an idea of the individual speed movement between both cars. The limo's white visor compared to the lexus should help. If you do not have login privileges, you'll have to download it from Google Drive here: https://drive.google.com/file/d/0BwrExtVD005ONTk4UTEzSWZCN1U/view?usp=sharing 2fps comp.mov