Chris Davidson

CE884 Z222 Converted: Elev 426.11 - 3.27ft = 422.84 490.9 - 422.84 = 68.06 65.68ft + 3.27ft = 68.95ft 68.95 - 68.06 = .89ft rifle barrel end above window frame sill. Difference between rifle barrel end height of z207 and z222: 1.17ft - .89ft = .28ft x 12" = 3.36 inches See post #187 graphic for contradiction.

Copied formula from post #105: The WC used 3.27ft as JFK's head elevation in every single frame surveyed (CE884), I can subtract that from the base elevation of the triangle ( 427.02) and add 3.27ft to the height (65.05) = 427.02 - 3.27 = street elev of 423.75 Subtract this street elev of 423.75 from the windowsill elevation of 490.9ft, since this is to the street. 490.9 - 423.75 = 67.15 and add 3.27ft to the height (65.05) = 68.32 elev And finally, subtract 68.32 - 67.15 = 1.17ft You can now apply that method to CE884 zframe222, which will tell you how high above the window frame sill the WC placed the rifle barrel end.

The gif was created from footage of the 1967 CBS special " The Warren Report". The distance between the two frames (11mph@3sec) in terms of (dummy travel from shooter) is approx 175 then 225 ft. I'm accentuating the rifle barrel angle/height change for you. The firing range was set up in Maryland to match the layout of Dealy Plaza. i.e. 6th floor height, Elm St slope, target distances, even a support box in some instances. Notice the change in angle/height of the rifle barrel as the dummy travels down the track.

We're still waiting. Quote from MW: I wrote my recent reply to this thread not for you and Chris but for new people who are curious about this case. If you do a search, McAdams is always going to come up first. If they arrive here to EF, they're obviously going to look through it and when they see this thread, it's really going to cause a lot of head shaking and browser closing. This thread is really falling into Jim Fetzer territory. Why don't you start your new thread and reply there? You can then get into another fruitless discussion about the validity of the film. There was a shot around the extant z207 location, there is a splice at 208, where are the sprocket holes in Groden's version for those frames? Most newbies can understand that correlation. Please don't answer here!!! Do it on your own dime!!! I'll take Shaw's expertise over your's any day.

Would the red arrows in the inset, point to the location on Gayle Newman and the cops chin strap, you are describing?

3.27ft vertical elevation relationship for "rifle angle to JFK 's head" WCD298 and extant z207-z208-(z222 Added on edit) WCD298 23.00degrees CE884 z207 21deg 50min = 21.83degrees Difference of 1.17degrees = 1degree 10.2 minutes CE884 z208-z222 = 21deg 34min - 20deg 23min = 1deg 11min difference.

Refer back to post #54, I tried to make it easy, but it's just beyond some to put two and two together. Even with supporting frames, photos and testimony.

I think we're getting closer. All roads point to a shot at extant 207 location. imo Melded into the shot ( we see on film at Station# 3+81.3. Specter/Shaneyfelt/Ford and the rest to make it happen Not enough time between shots. Two shooters. Keep the angle the same, keep the rifle above sill the same, but lose JFK's head height, now measure to the street.

David, The 61ft (red line through the word "tree") to the TSBD base, it's the first 61ft along the 171ft distance out to SS/FBI shot1. In other words, that 61ft distance includes no elevation change in the formula. Elevation of 429.7 is the same at the TSBD base (beginning of 61ft measurement) as it is at Station# 2+50.

Excerpt from post #122: This distance equals the exact length of the limo, provided from the WC document in post #3. 256.1" / 12 = 21.34ft Excerpt from post #123: And, with the limo at 21.34ft, this horizontal distance, converted back to a vertical elevation in terms of the Elm St. slope (1ft vertical per 18.3ft horizontal) = 21.34/18.3 = 1.166ft In essence, a match for the determination of the (rifle barrel end) elevation, 1.17ft above the windowsill ledge for surveyed zframe 207

Reconciliation for WCD298 + CE884 at extant z207-Station# 3+71.1 btw: 22.924degrees equals 167ft exactly. Excerpt from post#105: How did I arrive at 1.17ft above the windowsill ledge for surveyed zframe 207? There are a couple of ways to go about this: The easy way is look at survey frame z207, the 92.07 entry (right side of triangle) equals an elevation of 492.07ft The windowsill elevation is 490.9ft, look at the top right of the graphic within this post. Subtract these two and the difference is the rifle height above the windowsill. Or, Since I know the WC used 3.27ft as JFK's head elevation in every single frame surveyed (CE884), I can subtract that from the base elevation of the triangle ( 427.02) and add 3.27ft to the height (65.05) = 427.02 - 3.27 = street elev of 423.75 Subtract this street elev of 423.75 from the windowsill elevation of 490.9ft, since this is to the street. 490.9 - 423.75 = 67.15 and add 3.27ft to the height (65.05) = 68.32 elev And finally, subtract 68.32 - 67.15 = 1.17ft

The WCD298 LOS measurement from the snipers nest to JFK in limo is 167ft. Agreed. But this is at z207, not the 184ft LOS shot#1 location on the FBI/SS plat. The WCD298 graphic LOS I supplied does extend to the limo front, but JFK within the limo at this point is equal to z207 (check zfilm z207). That is the location I am pointing out. If you check CE884's entry for z207, the LOS from the snipers nest (rifle to JFK's head) is 174.9ft. A difference of approx 7.9ft between the LOS's. A few posts back, I plotted the limo traveling from z170-z184 at 14.4mph = 1.156 ft per frame If I make the assumption the limo was traveling the same speed when it hit z207, 23 frames (1.25 seconds) later, a 7 frame jump z161-z168 same station# 7 x 1.156 = 8.09ft difference This reconciles the difference's between the two LOS distances (167 -174.9) pertaining only to JFK's position at Station# 3+71.1 as entered on CE884. Does this make sense before we go on?

Any idea how the WCD298 measurements were created? Set aside the 167ft (shot #1) distance given from WCD298 for a moment. The WC298 graphic, when compared to extant z207, appears to be the same location. Added on edit: Now take a look at post #27

David, Also, take a look at post #72 again. This is one area that I disagree with Tom's conclusion about Shaneyfelt's erroneous assumption because of the mislabeled elevation of 419.07 instead of the correct 419.72. To put it another way, this is a telling sign that Shaneyfelt knew exactly what he was doing. His erroneous assumption in regards to the B.S shot location labeled shot#2 and distance to labeled shot#3 aka the Altgen's shot is 39'8" or 39.66ft. The limo length is 21.34ft. These two elements combined = 61ft. That was the reason why I converted it to 39.66ft. Now the odds become even more astronomical that none of the 61ft references are connected.

yet you mentioned Shaneyfelt maintaining the 61' distance throughout 419.07' = 232' - 61' = 171' from a point called 2+50 (which is 61' from 1+89) yet 2+50 appears to be the corner of the TSBD. Look back at the entire post #119. The match for 61ft you stated above. Shot #1 @ 171ft to Shot #2 @ 232ft = 61ft. Shot #2 @ 232ft according to Tom, via Robert West, was the moved location of the extant 313 headshot (notice there is no shot # designation for the extant headshot at elevation 418.35) back east up Elm St. What are the odds that the distance between a (supposed real shot @171ft and a relocated extant 313 headshot @ 232ft) would equal the distance in post#119 of 61ft? This is syncing in progress. imo Added on edit: Station# 2+50 is a location on Elm St, which is in alignment with the sniper's position, within the 6th floor window.

David, Did you mean to enter 419.07 (The misrepresented elevation of 419.72) in the equation as opposed to 418.07? chris

Refer to Post#44 for obtaining 13.44mph designation.

Post#56 excerpt: 13.44mph = 19.756ft per sec + .9ft (extant z161-z166) = 20.65ft total distance 13.54 vertical inches converted to horizontal distance = 13.54"/12" = 1.128333.. vertical ft. x 18.3(1horizontal ft.) = 20.648ft

Post #55: There is a 10" vertical difference between the sniper's perch boxes and the windowsill frame. Once again, what's up in the window has to sync with what's down on the street. In post 50, I show the speed of the limo as it pertains to the extant zfilm by plotting it. 5 x 1.08ft per frame = 5.4ft Remember, 1ft vertical = 18.3ft horizontal. Convert5.4ft to vertical: 5.4/18.3= .295 x 12" (1ft) = 3.54" 10"+ 3.54" equals a combined distance of 13.54 vertical inches. Post#160 excerpt: Take the distance not traveled, 3ft, added to the distance traveled from z168-171(.9ft) added to the distance from z185-186 (1.5ft) = 5.4ft.

Just in case it was forgotten: 48fps/18.3fps = 2.622 2.622 x 7frames = 18.35 frames = 1 second in terms of 18.3fps

Excerpt carried over from post #84: Looking at CE560, a few remarks are in order. To figure out the exact vehicle speed Frazier uses, note the line starting with: Ave Vel= Average Velocity Ave Vel = 175/2070 = .085 sec 1sec/.085 = 11.764…. x 1.4ft = 16.47ft per sec =11.2mph Added on edit: Or, this way: .085/.0546(1frame/18.3fps) = 1.556frames 1.4ft per 1.556frames = .8997...ft per frame x 18.3fps = 16.465ft per sec/1.47(1mph) = 11.2mph Mr. SHANEYFELT. Yes; because we were able to determine the speed of the camera, and thereby accurately determine the length of time it takes for a specific number of frames to run through the camera at this 18.3 frames per second, and having located these frame positions in the street, we took the farthest distance point we had in the Zapruder film which was frame 161 through frame 313. This was found to run elapsed time from the film standpoint which runs at 18.3 frames a second, runs for a total of 8.3 seconds. This distance is 136.1 feet, and this can be calculated then to 11.2 miles per hour. The WC is trying to force a round peg in a square snipers nest at an ideal 11.2mph.

Finally, The total distance traveled (according to WC CE884) from Z168-z186 = 21.6ft (station# 3+29.2 - 3+50.8) 21.6ft - 5.4 ft = 16.2ft, a match How could Myers ever sync films when he has the limo traveling at 11.2 mph when plotted it's traveling at (added on edit) 14.449 14.40 mph? That's why he left off distances/times after his 150-175 frame span.

Since it is almost a one second time span, let's deal with the immediate Z168- Z186 span on the WC CE884 plat. Take the distance not traveled, 3ft, added to the distance traveled from z168-171(.9ft) added to the distance from z185-186 (1.5ft) = 5.4ft. Now add 5.4ft to the extra .088ft difference between CE884 and z film plotting = 5.49ft Z168-Z171 = 3 frames@.9ft traveled when converted to an 18.3 fps equation = 18.3/3 = 6.1 x .9ft = 5.49ft. And there you go, the missing .088ft appears when the conversion in mph is applied. And, since 16.2ft was only over 18fps, not quite 1 second, let me convert that to one second: 18.3/18 = 1.01666… x 16.2ft = 16.47ft per sec = 11.2mph SEE MYERS EXCERPT FOR THE MATCH