Chris Davidson Posted March 7, 2012 Share Posted March 7, 2012 This is the easiest way I can show you. It's what's revealed when you hide the different elements of a MATH equation. At 13.95 seconds til the headshot, Myer's has JFK aligned with the corner of the TSBD. What he wants you to do is count down to frame 313, forget about the TSBD corner starting point, and base all your calculations to 313, which he has done. Instead of that, let's just subtract his elapsed time from the "13.95 sec/JFK aligned with the TSBD corner" mark and work from there. Remember, the Zapruder camera was running at 18.3 Frames Per Sec, regardless of whether or not you think there is limo footage before Zframe133. If you want me to explain this in relationship to the WC calculations also, I can do that. It all has to do with ratios and averages. And most importantly, how to hide 30ft within the confines of an altered film. Enjoy, chris Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 7, 2012 Author Share Posted March 7, 2012 Let me try and tie the chart to an example. If you notice the bottom entry of 160 frames@5.59seconds, you get a Frame speed of 28.62 a second. Obviously, this doesn't work. But, in the same time of 5.59 seconds, 134 frames would give you 24frames per sec. 24 x 5.59= 134 The difference in frame count between 160 and 134 is 26 frames. The distance difference between JFK in the limo and the limo front is 15-15.25ft. The gif shows that distance traveled. It occurs in 13 frames. 13 frames for 15ft = 26frames for 30ft. 30ft is the adjustment needed for the Altgen's headshot. chris Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 7, 2012 Author Share Posted March 7, 2012 (edited) Did you know that 313frames/13 frames@15ft=24sec. You see, that would be an average. chris Edited March 7, 2012 by Chris Davidson Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 7, 2012 Author Share Posted March 7, 2012 13 frames @15ft converted to 18.3fps= 18.3/13=1.407 Actually, it's closer to 15ft3in or 15.25ft 15.25ft x 1.407=21.467ft per sec 21.467 x 1.47(1mph)=14.6 mph chris Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 7, 2012 Author Share Posted March 7, 2012 (edited) The distance from frame 1(JFK aligned with the TSBD corner)-Z161 is 85ft. There is a 15ft adjustment included in the WC scenario which sets the distance at 100ft. 161frames/18.3fps=8.797seconds 100ft/8.797sec=11.367ft per sec 11.367/1.47(1mph)=7.73mph If I want to create an average vehicle speed over the entire distance of frame1 to 313 with the above scenario, I need to incorporate WC calculations from CE884, So frame 161-313 is 152 frames @136.1ft traveled. There is one problem though, I will not be able to use 18.3fps as my frame rate. I'll have to use 24fps. 152frames/24fps=6.33sec 136.1ft/6.33sec=21.5ft per sec 21.5ft per sec x 1.47(1mph)=14.62mph Now average the above scenario's together since we are talking about 152 and 161 frame scenarios. 7.73+14.62=22.35/2=11.17mph Now run the WC scenario which uses 18.3fps with the same numbers above: 152/18.3=8.30 seconds 136.1ft/8.3 seconds=16.397ft per sec 16.397ft per sec/1.47(1mph)=11.154mph Do you see how you can hide distances and frame rates within a bigger picture? chris Edited March 7, 2012 by Chris Davidson Link to comment Share on other sites More sharing options...
Daniel Burnet Posted March 7, 2012 Share Posted March 7, 2012 (edited) Edited August 28, 2015 by Daniel Burnet Link to comment Share on other sites More sharing options...
Daniel Gallup Posted March 7, 2012 Share Posted March 7, 2012 The distance from frame 1(JFK aligned with the TSBD corner)-Z161 is 85ft. There is a 15ft adjustment included in the WC scenario which sets the distance at 100ft. 161frames/18.3fps=8.797seconds 100ft/8.797sec=11.367ft per sec 11.367/1.47(1mph)=7.73mph If I want to create an average vehicle speed over the entire distance of frame1 to 313 with the above scenario, I need to incorporate WC calculations from CE884, So frame 161-313 is 152 frames @136.1ft traveled. There is one problem though, I will not be able to use 18.3fps as my frame rate. I'll have to use 24fps. 152frames/24fps=6.33sec 136.1ft/6.33sec=21.5ft per sec 21.5ft per sec x 1.47(1mph)=14.62mph Now average the above scenario's together since we are talking about 152 and 161 frame scenarios. 7.73+14.62=22.35/2=11.17mph Now run the WC scenario which uses 18.3fps with the same numbers above: 152/18.3=8.30 seconds 136.1ft/8.3 seconds=16.397ft per sec 16.397ft per sec/1.47(1mph)=11.154mph Do you see how you can hide distances and frame rates within a bigger picture? chris I am wondering Chris how you integrate a limo stop into your analysis. Based on eyewitness testimony, as best as I can understand it, the limo was slowing down and stopped after or during the headshot, if indeed there was but one, as I am inclined to think based on the Dallas' testimony. The extant Z-film does show the limo slowing below the 11 mph average right before the head shot, but I believe the limo stop was removed, along with ejecta exiting out of the back of Kennedy's head, which would have been a major problem for framing Oswald for the crime. Would be interestd on your take,and thanks in advance. Respectfully, Daniel Link to comment Share on other sites More sharing options...
Daniel Burnet Posted March 7, 2012 Share Posted March 7, 2012 (edited) Edited August 28, 2015 by Daniel Burnet Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 7, 2012 Author Share Posted March 7, 2012 http://i140.photobucket.com/albums/r25/123steamn/VehicleSpeed-2.jpg The supplied chart may not make sense to you at first, so I will break some of it down for you. The average MPH listing in the upper far right corner of each chart lists 3.74 and 2.24 mph. Remember, the WC was using averages and ratios to figure out how to make the film work, along with some obvious splices. The 3.74 mph figure is arrived this way: 100 frames @30ft@18.3 fps 100/18.3=5.464seconds 30ft/5.464=5.49ft per sec 5.49/1.47(1mph)=3.735mph Then they used the same distance and frame rate for 166.66 frames. If you look to the left side of the charts, the entry for the far left upper and lower column is 3 and 5 frames. 5/3=1.666666667 or 166.66 frames 166.66/18.3=9.107seconds 30ft/9.107sec=3.294ft per sec 3.294/1.47(1mph)=2.24mph chris Link to comment Share on other sites More sharing options...
Daniel Burnet Posted March 7, 2012 Share Posted March 7, 2012 (edited) . Edited August 28, 2015 by Daniel Burnet Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 7, 2012 Author Share Posted March 7, 2012 So what does the previous posting pertain to. WC CE884 of course. http://i140.photobucket.com/albums/r25/123steamn/Frame161-2.png You'll notice the top two entries are frame 161 and 166. The station# for each is 3+29.2 and 3+30.1 the ratio between these two is: 29.2/30.1=.97ft If I was working with 2 different frame rates with a 15ft marker in mind , I would need to calculate the differences between the two. Difference between frame 161and 166 = 5frames 5FRAMES/18.3FRAMES PER SECOND=.273sec 5FRAMES/24 FRAMES PER SECOND=.208 .273 x 15ft=4.095ft .208 x 15ft=3.12ft 4.095ft-3.12ft=.97ft That is a match for the difference between frame 161 and 166 distance traveled. If you look at the difference in the rest of the entries, you come up with approx 1 frame per 1 foot traveled. Distance between frame 161 and 166 is an adjustment made for a film at 2 different frame rates with a 15 ft length as the mark. chris Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 7, 2012 Author Share Posted March 7, 2012 The distance from frame 1(JFK aligned with the TSBD corner)-Z161 is 85ft. There is a 15ft adjustment included in the WC scenario which sets the distance at 100ft. 161frames/18.3fps=8.797seconds 100ft/8.797sec=11.367ft per sec 11.367/1.47(1mph)=7.73mph If I want to create an average vehicle speed over the entire distance of frame1 to 313 with the above scenario, I need to incorporate WC calculations from CE884, So frame 161-313 is 152 frames @136.1ft traveled. There is one problem though, I will not be able to use 18.3fps as my frame rate. I'll have to use 24fps. 152frames/24fps=6.33sec 136.1ft/6.33sec=21.5ft per sec 21.5ft per sec x 1.47(1mph)=14.62mph Now average the above scenario's together since we are talking about 152 and 161 frame scenarios. 7.73+14.62=22.35/2=11.17mph Now run the WC scenario which uses 18.3fps with the same numbers above: 152/18.3=8.30 seconds 136.1ft/8.3 seconds=16.397ft per sec 16.397ft per sec/1.47(1mph)=11.154mph Do you see how you can hide distances and frame rates within a bigger picture? chris I am wondering Chris how you integrate a limo stop into your analysis. Based on eyewitness testimony, as best as I can understand it, the limo was slowing down and stopped after or during the headshot, if indeed there was but one, as I am inclined to think based on the Dallas' testimony. The extant Z-film does show the limo slowing below the 11 mph average right before the head shot, but I believe the limo stop was removed, along with ejecta exiting out of the back of Kennedy's head, which would have been a major problem for framing Oswald for the crime. Would be interestd on your take,and thanks in advance. Respectfully, Daniel Hi Daniel, I'm not going to integrate a limo stop in my analysis. That is not what I am trying to accomplish. I am trying to expose a film created from different frame rates, created by the WC, to cover up a shot some 30ft farther down Elm than the 313 headshot. chris Link to comment Share on other sites More sharing options...
Daniel Gallup Posted March 8, 2012 Share Posted March 8, 2012 (edited) I am wondering Chris how you integrate a limo stop into your analysis. Based on eyewitness testimony, as best as I can understand it, the limo was slowing down and stopped after or during the headshot, if indeed there was but one, as I am inclined to think based on the Dallas' testimony. The extant Z-film does show the limo slowing below the 11 mph average right before the head shot, but I believe the limo stop was removed, along with ejecta exiting out of the back of Kennedy's head, which would have been a major problem for framing Oswald for the crime. Would be interestd on your take,and thanks in advance. Respectfully, Daniel In fairness, I believe that the limo stop is at least somewhat disputed, but I am also interested in how it WOULD affect the analysis, regardless of whether one accepts it or not. Hi Daniel, this is the other Daniel. Yes the limo stop is most certainly disputed!!!! And I liked the way you phrased the question: how would Chris figure in the stop, whether it happened or not. May I recommend David Lifton's essay "Pig on a Leash" in The Great Zapruder Film Hoax, pp. 333-4 (re Sylvia Meagher) and pp. 344-5 wherein Lifton details his interviews with those individuals who were situated at the limo at the time of the headshot, interviews in 1971 before the extant Z-film was shown to the public. See also Toni Forster in the K. A. Chronicles, summer 2000. Debra Conway broke open the case favoring alteration for me with that interview. See also the essay Delay on Elm St. in Murder in Dealey Plaza. I hope Chris answers our question. best, Daniel Edited March 8, 2012 by Daniel Gallup Link to comment Share on other sites More sharing options...
Daniel Gallup Posted March 8, 2012 Share Posted March 8, 2012 The distance from frame 1(JFK aligned with the TSBD corner)-Z161 is 85ft. There is a 15ft adjustment included in the WC scenario which sets the distance at 100ft. 161frames/18.3fps=8.797seconds 100ft/8.797sec=11.367ft per sec 11.367/1.47(1mph)=7.73mph If I want to create an average vehicle speed over the entire distance of frame1 to 313 with the above scenario, I need to incorporate WC calculations from CE884, So frame 161-313 is 152 frames @136.1ft traveled. There is one problem though, I will not be able to use 18.3fps as my frame rate. I'll have to use 24fps. 152frames/24fps=6.33sec 136.1ft/6.33sec=21.5ft per sec 21.5ft per sec x 1.47(1mph)=14.62mph Now average the above scenario's together since we are talking about 152 and 161 frame scenarios. 7.73+14.62=22.35/2=11.17mph Now run the WC scenario which uses 18.3fps with the same numbers above: 152/18.3=8.30 seconds 136.1ft/8.3 seconds=16.397ft per sec 16.397ft per sec/1.47(1mph)=11.154mph Do you see how you can hide distances and frame rates within a bigger picture? chris I am wondering Chris how you integrate a limo stop into your analysis. Based on eyewitness testimony, as best as I can understand it, the limo was slowing down and stopped after or during the headshot, if indeed there was but one, as I am inclined to think based on the Dallas' testimony. The extant Z-film does show the limo slowing below the 11 mph average right before the head shot, but I believe the limo stop was removed, along with ejecta exiting out of the back of Kennedy's head, which would have been a major problem for framing Oswald for the crime. Would be interestd on your take,and thanks in advance. Respectfully, Daniel Hi Daniel, I'm not going to integrate a limo stop in my analysis. That is not what I am trying to accomplish. I am trying to expose a film created from different frame rates, created by the WC, to cover up a shot some 30ft farther down Elm than the 313 headshot. chris As a math teacher I should be interested in your study, Chris, and I thank you for summarizing succicintly exactly what you are trying to show. But all this still begs the questions: why do you suppose it was the WC which created the fradulant film, and not the CIA; and how does the most central aspect of the that fraud, the limo stop, figure into the numbers? Because the limo does show a distinct slowing, even in the extant film, before 313. If your study is about averages, would it not do to take smaller and smaller time increments as one nears 313? Best regards, Daniel Link to comment Share on other sites More sharing options...
Chris Davidson Posted March 8, 2012 Author Share Posted March 8, 2012 Referring back to the chart with the 3.74 and 2.24 mph entries. The top two rows go like this: FRAME TO FRAME #of Frames Distance Traveled 168-171 3 .9ft 171-185 14 19.2 ft Think in terms of differences: 11 frame difference and 18.3ft difference. Now create a ratio from it: 18.3/11=1.666 11/18.3=.60 Bottom Rows: FRAME TO FRAME #of Frames Distance Traveled 161-166 5 .9ft 166-185 19 19.2ft Once again, differences 14 frames 18.3ft Ratio= 18.3/14=1.307 14/18.3=.765 Keep these numbers in mind!!! chris Link to comment Share on other sites More sharing options...
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