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6 hours ago, Chris Davidson said:

The span of 28.5ft (distance from POSITION A to Station# 250.0) with an elevation change of 1ft equals a 2 degree slope.

This will help(mathematically) in the exacting of the listed .56ft lead bullet height on CE560.

39774549234_cb090e4b79_o.png

 

The three common entries used to complete the feat:

3.27ft

3.13degrees 

10.2ft

The more exact distance would be 10.2351ft

10.2351/3.27 = 3.13

 

 

 

 

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Use this link to help decipher survey z207:

http://educationforum.ipbhost.com/topic/22692-swan-song-math-rules/?do=findComment&comment=330706

The 3.27ft vertical elevation used in CE884 for JFK's height converts to 1deg.

There was a 1.13deg difference between POSITION A and Station 250.0

Converting that difference (in terms of elevation) :

3.27 x 1.13 = 3.695ft

3.695ft - 3.27ft = .425ft difference

If this answer sounds familiar, it should:

 

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If you look at these two entries in the z207 decipher link:

3.27FT/60MIN = .0545 vert ft. per min

1ft vertical/18.3ft horizontal (ElmSt slope) = .0546vertical ft /1ft horizontal

There is one more entry needed to connect the common ratio among them:

1frame/18.3frames = .0546 seconds per frame

Slick how that works.

P.S.  3.276/60 = .0546 exactly

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A few posts back, I mentioned how there were a few pieces to getting us the CE560 (.56ft) bullet lead height input.

We already have .425ft of it.

Now that we realize a 1 to 1 ratio is in play, we can apply that to Frazier's entry of "bullet time to impact" (.085 sec) and "limo distance traveled" (1.4ft????)

1 zframe = .0546sec = .0546 vert ft.

Frazier's .085sec / .0546 = 1.5567 zframes and 1.5567 horiz ft traveled.

Frazier's .085 sec = .085 vert elev

 

 

 

 

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9 hours ago, David Josephs said:

Ergo, we do not get a film speed between 16 and 18 feet per second... but an impossible 18.3 feet per second...

what a coincidence...  well done

:cheers

David,

I take it you meant frames per sec,  not feet?

The 1 to 1 ratio applies to the anywhere from (10.2ft-10.24ft) span =.56ft = 6.7inch WC adjustment.

1.525frames per inch = 18.3frames per 12inches = 1second per 12inches
or 1/1.525 = .655…inches per frame x 10.22 frames = 6.7… inches = CE560

My conversion using the z207 decipher below:

1/1.528 = .65445.. x 10.24 framest = 6.7 inches = CE560

 

 

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The acoustical closely aligns with the 10.22-10.24, a .02 frame span difference. 

z313 - (104.31frames)= 5.7 seconds = z208.69

From z207 -z208.69 = 1.69frames

If you look at CE884 z207-z222 = 14.8ft per 15 frames (12.28mph) = .986666... ft per frame

.98666... x 1.69 frames = 1.6674ft

The 1 to 1 ratio of frames to horizontal ft would dictate a :

1.69ft - 1.6674...ft  = .0225ft difference, which pretty much matches the 10.22-10.24 frame span difference.

In terms of speed, instead of 12.28mph, an average of 12.44mph would give you the 1.69 frame duration.

40016500461_a8d0a032de_b.jpg

 

 

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12 hours ago, Chris Davidson said:

David,

I take it you meant frames per sec,  not feet?

The 1 to 1 ratio applies to the anywhere from (10.2ft-10.24ft) span =.56ft = 6.7inch WC adjustment.

1.525frames per inch = 18.3frames per 12inches = 1second per 12inches
or 1/1.525 = .655…inches per frame x 10.22 frames = 6.7… inches = CE560

My conversion using the z207 decipher below:

1/1.528 = .65445.. x 10.24 framest = 6.7 inches = CE560

 

 

You can match the above bolded equation to (10" vert. = 15.25ft horizontal)  multiplying by a factor of 10:

15.25 frames = 10 inches 

This in keeping with the 1-1-1 ratio.

 

 

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Others like to refer to them as simple mistakes.

Here's the next one:

The elevation change for the 152 frame span = 429.25 - 421.75 = 7.5ft

152.5 frames =100 inches = 8.333..ft

What do you think the difference between these two elevations is?

Might it be the 10" vert = 15.25 horizontal drop the WC forced you to eat from z161-z166.

You know, they fed you d-g sh-t and told you it was prime rib.

39828110044_e3db543b39.jpg

 

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