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Why divide 7.4745 mph by 2 when you leave it alone at 7.60 mph

7.33ft x   (18.3/12)1.525 = 11.178...ft per sec    / 1.47 = 7.60… mph
7.205ft x (18.3/12)1.525 = 10.987625ft per sec / 1.47 =7.4745…
/ 2 = 3.737… mph

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David,

What happens to the limo speed on film when it's moving at 3.74mph  3.737… mph  and half the frames are removed?

Edited by Chris Davidson
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This is how I would distinguish the difference between the 7.33ft/7.205ft which equates to 7.6mph/7.474...mph using what I have already supplied:

1.5mph x 1.47ft per sec = 2.205ft

4frames/18.3 = .2185…sec

.2185sec… x 2.205ft = .4819ft…

.4819ft… / 4frames = .1204ft per frame

7.205ft + .1204ft = 7.325ft…

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So we're back to the change from 48fps to 24fps yet there is another conversion to 18.3fps requiring the removal of another 23.75% of the frames if 50% of ALL the frames are removed...

Q1:  Which 4 frames are you talking about?  We were talking about 301-313 or 12 frames to travel 7.205' or 7.33'
Q2: If 50% of the frames are removed from this sequence, then much more than 66% would need removing elsewhere to wind up with 18.3... PLUS if Nix is filming at his 16-18fps the 24fps cutdown will not match...  Using 50% just because the results are closer to what you want to see doesn't mean that 50% is correct...  on the flip side during 285-334 it is very possible that only 50% are removed there, starting at 161 yet changing that to 168, helps with some more frames, some more distances and speeds.

According to your calcs,there would have been 24 total frames from 301 to 313; total distance 7.205'.  7.205/24=.3002 feet per frame = 3.74mph
(How do you get 24 frames as a starting point when the camera speed is either 16 or 48fps?)
According to mine there would have been 32 total frames from 301 to 313 (@ 48fps); same distance  7.205/32=.22516' per frame = 2.81 mph * 2.623 (48/18.3) = 7.37mph at 18.3fps

So again, which 4 frames within 301-313 are you talking about?

Edited by David Josephs
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2 hours ago, David Josephs said:

So we're back to the change from 48fps to 24fps yet there is another conversion to 18.3fps requiring the removal of another 23.75% of the frames if 50% of ALL the frames are removed...

Q1:  Which 4 frames are you talking about?  We were talking about 301-313 or 12 frames to travel 7.205' or 7.33'
Q2: If 50% of the frames are removed from this sequence, then much more than 66% would need removing elsewhere to wind up with 18.3... PLUS if Nix is filming at his 16-18fps the 24fps cutdown will not match...  Using 50% just because the results are closer to what you want to see doesn't mean that 50% is correct...  on the flip side during 285-334 it is very possible that only 50% are removed there, starting at 161 yet changing that to 168, helps with some more frames, some more distances and speeds.

According to your calcs,there would have been 24 total frames from 301 to 313; total distance 7.205'.  7.205/24=.3002 feet per frame = 3.74mph
(How do you get 24 frames as a starting point when the camera speed is either 16 or 48fps?)
According to mine there would have been 32 total frames from 301 to 313 (@ 48fps); same distance  7.205/32=.22516' per frame = 2.81 mph * 2.623 (48/18.3) = 7.37mph at 18.3fps

So again, which 4 frames within 301-313 are you talking about?

Q1. The Itek study is four frames per entry:

A2-A6 = z285-z289

A6-B = z289-z293 which is where the aberration in limo speed occurs.

Q2. z289 + (48 frames /2) = 24 = z313

I'm not describing four frames within z301-z313.

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On 5/5/2017 at 9:59 AM, Chris Davidson said:

David,

What happens to the limo speed on film when it's moving at 3.74mph  3.737… mph  and half the frames are removed?

11.2mph = 7.475 + 3.735

3.735 = 1/2 of 7.47

3.735 = 1/3 of 11.2

7.47 = 2/3 of 11.2

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On 5/2/2017 at 2:01 PM, Chris Davidson said:

Dr.Shaw stated this:

If Dr.Shaw had listened to Dan Rather's description of Connally's actions/position, knowing that Rather was trying to connect it back to the TSBD, he would have realized or did realize where that shot actually came from.

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The red line provides a LOS traversing the light post and the Z pedestal.

In other words, if you are Zapruder at approx z273 and you tilt the camera upward, guess who/where you would see on the other end?

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Here's what it looks like plotted:

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So, what am I looking at during Z273?

Edited by David Josephs
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The rooftop of the Dallas County Criminal Courts building is listed as 120ft high.

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3 minutes ago, David Josephs said:

So, what am I looking at during Z273?

David,

You're looking at what's going to give you a 25 degree angle from the Dallas County Criminal Courts.

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The "base" distance from z273 to the Criminal Courts building is 242.8ft.

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The base of the Criminal Courts building appears to be at elevation 430ft.

The limo elevation at z273 = 430 - 12.97ft (that's using z313 @ elevation 418.48 per CE884).

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The height needed for a 25 degree downward angle is 113.2ft.

113.2 - 12.97ft = 100.23ft approx.

100ft up in the corner of the Criminal Courts building is where you'll find the shooter.

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