Chris Davidson

20.65ft was the horizontal sync for the vertical range of JFK's head above the pavement (52.78inches and the 39.24inches = 3.27ft used in CE884) 52.78" - 39.24" = 13.54 inches /12 = 1.12833ft.... x 18.3ft(Elm St slope conversion 3.13°) = 20.6485ft = the link below. That would be an exact match for 43 of 48 frames @ .4802ft per frame. Of course the 13.54" consisted of the 10" drop + 3.54" = (3.54/12 = .295ft x 18.3ft = 5.3985ft) = 20.648ft

The above equation uses the extant z film(z154-z166) for the 5.4ft distance (5 frames @ 1.08ft per sec=13.44mph). This does not include the .9ft lost from the true speed for a distance of 5.4 + .9 = 6.3ft. Look back to the 1.166 ratio to connect the difference: 6.3/1.166 = 5.4ft

Continuing with 20.65ft: The other CE884 gave us a range of 5 frames z161-z166. Converted from 43 of 48 frames/1sec 43 x .4802ft per frame = 20.648ft

This .9ft remnant is very instrumental when put back into its proper context to fit the official narrative: 19.7592 + .9 = 20.6592ft 20.6592ft/23.0472ft = .896/1 ratio

btw, The final CE884 version reduced the .9ft span from 7 to 5 frames. This was to sync with the final CE884 specs of z161-z313 (136.1ft traveled @8.3 sec@18.3frames per sec. The ratio being the same as reducing 48 frames down to 43 43/48 = .8958/1 136.1/8.3 = 16.397ft per sec / 18.3frames per sec = .896ft per frame Both equating to 16.397 / 1.47 = 11.154mph

Which in turn, circles us back to our 8% solution starting from 18.3, both in terms of frame rate and Elm St slope conversion. 18.3 x 1.08 = 19.76 19.76 x 1.08 = 21.34 21.34 x 1.08 = 23.0472

The 1.1664... ratio can now be applied to the frame rate for syncing. 48fps / 1.1664.. = 41.15frames x .4802ft per frame = 19.76ft per sec 48- 41.15 = 6.85frames = 7 whole frames = The difference in frame count between the two CE884's physical location for Station# 3+29.2 = z161 and z168 = 7 frames.

Not only is it wise to keep the distance differences in mind, but the ratio's as well. Once the 8% squeeze/spread is applied, the ratio of the limo length becomes: 23.0472/19.759 = 1.166/1 This ratio equals the limo length to vert (1ft per 18.3horizontal ft.) Elm St slope ratio: 21.34/18.3 = 1.166/1

Retarding the same distance.

In case you had forgotten what matches 19.75ft: 10" drop / 12" = .833... x 18.3(vert to horiz) = 15.25ft + 5.4ft (5 frames @ 1.08ft per sec=13.44mph) = 20.65ft - .9ft (bogus distance traveled CE884 z161-z166) = 19.75ft 13.44mph x 1.47ft per sec = 19.75ft per sec Hopefully the WC/Myers synchro from above and at street level is becoming clearer for you.

In case you had forgotten what constitutes the limo length.

Difference in limo (spread and squeeze) distance = 23.0472ft - 19.759ft = 3.288ft per sec

Speaking of limo exercises and the Myers 8% solution: 21.34ft / 1.08(squeeze) = 19.759ft per sec 

Speaking of limo exercises and the Myers 8% solution: 21.34ft x 1.08(spread) = 23.0472ft per sec

The difference between inside radius and outside radius was 24.52ft. Added was the Towner gap of 5.625ft (In the end, I think they "powers that be" used 5.5ft) This leads up to, but not including the .9ft jump from z161-z166. 24.52+ 5.625 = 30.145ft / 9.125 sec (167 Towner frames@18.3 frames per sec) = 3.3ft per sec This quite closely matches the speed of the limo at CE884 Z161-Z166 = 3.294ft per sec. In other words, the entry for z161-z166 is a major remnant of the (3.29ft per sec = 2.24mph) adjustment being applied to the overall equation.

It would have been easier to give us the distance traveled between the Towner end and the Z beginning. That would be 5.625ft. Sorry, but 15 frames @ 5.625ft using 18.3frames per sec = a limo traveling 4.66mph. When the Martin film (an 8mm camera)@18.8frames per sec is plotted (16 frames) through the Towner/Z gap the limo is traveling at 11.33mph. This coincides with the average consisting of the last 20 Towner frames and the first 16Z frames. 7.78mph + 14.88mph = 22.66mph/2 = 11.33mph Added on edit: 6.18 frames (11.33mph - 18.3frames per sec) would have elapsed to cover the gap, not the 15 + 118 =133 that you were led to believe.

Slice the limo up and integrate it with Myers and CE884. 21.34ft/.18 = 118.55 frames (+/- 1frame)

Pamela, That's not the way it works. imo He specifically states exactness in regards to his Epipolar multi-film synchronization project. The limo measurement inaccuracy would be just another in a long line of adjustments to have his work sync with the WC results. When you have two projects that use incorrect info, but result in the same outcome, that is a big no no. As an example, how many 8mm camera's film at a frame rate some 26% faster than (18fps) than their factory specs dictate. Both on the same day, filming the same event. When the correct limo length is used in ongoing calculations, some rather revealing insights occur.

Do you think that Myers retarding (keeping eastward) the limo distance 30.92ft at the front end would have any relationship to the distance of 30.856ft at the back end? Since the limo length was used as part of the equation which ultimately led to the distance between the (WC documented) Altgen's and extant Z313 shot, would it be appropriate to apply the Myers % adjustment accordingly?

Myers plat enlarging to 108% can be used to sync his work with the incorrect (CE884 WC final version) Station# 3+30.1 = Z166 His total distance traveled for Towner's film = 86.38ft as he used an inside radius = drivers side rear tire as his marker. The distance traveled using (JFK within the limo) an outside radius, as the marker = 110.9ft 86.38/1.08 = 79.98ft 110.9 - 79.98ft = 30.92ft Push forward to Z133 @ Station# 2+99.0 + 30.92ft = Station# 3+29.92 The link spells out the frame distance traveled for z161-z166 @ .18ft per frame Station# 3+29.92 + .18ft(1frame) = Station# 3+30.1 = (CE884 WC final version) Station# 3+30.1 = Z166 Myers uses 167 frames as his Towner total. The extra frame needed comes via the bottom of that link which states: Now refer to the distance per frame traveled from CE884 z161-z166 = .18ft per frame traveled The WC difference comes in the span of z133-z161 = 30.2ft (Station# 299- 329.2) 30.2 /.18 = 167.77 vs 167 = 1extra frame Or just take Myers landing at 3+29.92 - Z133(3+29.2) = .72ft + .18ft (1frame) = .9ft .9ft = the total distance traveled Z161-166 from CE884 WC final version. 108% is rather interesting moving forward!!!!

Chris, I support Dr.Costella's theory too.

My conversion for 1mph is and always has been 1.47ft per sec. We're done Butler. Take a surveying class. Once you're done with that, come back and explain this distance for everyone. It should be quite an event. You were given the pieces to "skin the cat" and you gave it an awful haircut instead.

The cycle cop travels approx 120ft @7.21sec@18.3fps = 11.3mph average. The best distances I arrive at for the rest are in the graphic. Since the white car doesn't appear in the last frame of z1-132 (big variable) the limo is at least : 120 + 20 + 157.5 - 10ft overlap = 287.5ft behind the cycle cop at z132 within the graphic. I don't see a problem with Myers applied average speed to the limo on Houston St at 9.3mph. Someone can check that if so inclined. 9.3mph = 13.67 ft per sec 157.5ft/13.67 = 11.5 sec + 7.21 sec = approx 18.71sec at least, ahead of the limo. If there is more detailed info then you can add/subtract what you need to. Added on edit: Towner film( Myers adding 7 frames at TSBD splice): (167/18.3 = 9.125sec) +(157.5ft/13.67 = 11.5 sec) = 20.625sec 20.625sec - 18.71 sec = 1.91sec Difference in Myers frame rate for Towner at 22.8 and 18.3fps over 167 frames = 1.8 sec.

If there is any interest in other aspects (imo) related to this ghost image, I further expanded on it here: http://forum.assassinationofjfk.net/index.php/topic/1407-secret-service-and-fbi-made-reenactment-films-why/?p=8995 David Healy's excellent "Technical Aspects of Film Alteration" and Dr.John Costella's expertise along with David Josephs (voluminous mind boggling research) and many others, carry on. John Butler, there are many ways to "skin a cat", we choose different methods.