Chris Davidson

Altgen's 6 taken at approx z255 = 486-255 = 231/18.3 = 12.62sec while the Wiegman/Bell sync at least 22sec after the headshot, followed by Couch does not = Altgens crossing the street a few seconds after Altgens 6? Altgens is seen(in Couch) crossing the street as Wiegman makes his run down the knoll. Look closely down the street toward the lightpost. Guess who that is crossing? https://drive.google.com/file/d/0BwrExtVD005OS3QxMXNBemRkSGs/view?usp=sharing

Answers in red.

That's because the previous inset shows the same cycle cop in Couch, after he somewhat traverses the camera cars in Couch. This occurs while Wiegman (a camera car photographer shown in Couch) runs down the slope.

No, the camera cars have not left the area. They are approaching Wiegman (red box) who films the inset(lower right corner). I suggest watching the Couch film which includes Wiegman's partial run down the grassy knoll if you want to see the other camera cars(and cycle cop movement) as they start/move down Elm before Wiegman films the inset.

Gene, Z or whomever started walking toward the "TSBD/his office" quite possibly landed in the pergola first. I'm not saying these are the same two people either. Either way, this creates a problem for Zapruder's spoken actions. Z's actually in another film that day, I'll discuss that later.

Adam, Start a new topic named "Conversions" or something like that. Then repost your previous response and I will reply. I believe the answer you are seeking may not be indicative of the figures you are providing. Or, I'm reading your question incorrectly. Let's make sure before we go on. Chris

Understanding the WC magical mystery show. https://drive.google.com/file/d/1GwCfer-uv58dgbtkJ-Zg6tqYh4al2_BH/view?usp=sharing

The range of z210-z222 (12.5ft/12frames = 1.041ft per frame) on CE884 is a little more concentrated than what is possible to measure in terms of stationary landmarks. z206.5 -z230.5 = .958ft per frame iow, z210-Station# 3+73.4 + 7.9ft = Station# 3+81.3 = bullet strike 7.9ft/1.041ft per frame = 7.5888frames = Z217.588 From z207-z217.588 = 10.588frames z207-z217.588 = 10.2ft/10.588frames = .963ft per frame

Adam, Answers in Red

Videos: https://drive.google.com/file/d/1bNxJe52IUUt9cr_BPhoy41gDcRf3er3B/view?usp=sharing https://drive.google.com/file/d/1sdECH4XR_tcx8S3tjmiun1uDREeLCBQx/view?usp=sharing

Adam, In essence, it sounds like you are trying to recreate/exact CE884 (There are two versions). Publicly released version: https://www.history-matters.com/archive/jfk/wc/wcvols/wh17/html/WH_Vol17_0464b.htm It is the method that was used originally (on the ground), although once they got their initial starting point (say Z161), I believe they just measured to the next succeeding entry. I do have a brief video of this method starting from Position A to Z161. Will post later if interested.

Taking into consideration the 10.2ft distanced traveled from pull of trigger, the limo drop in elevation = 10.2ft/18.3ft = .557 x 12 inches = 6.68 inch drop. This lead is reflected in CE560 documentation. The problem is, it's supposed to represent a shot from the 6th floor snipers nest with a car traveling at 28+ mph(see CE884 Orange Version z207-z208).

The 315ft measurement was down to the sidewalk. Sorry about that. 133yds to the top of the south knoll. .505 sec x 18.3 = 9.2415 frames x 1.041ft per frame (average limo speed z210-z222) = 9.62ft + .58ft (7 inches = torso depth) = 10.2ft z207 = Station# 3+71.1 Shot#1 = Station# 3+81.3 = Elevation 423.07 10.2ft 423.07 + 3.54ft (42.5inch above ground bullet hole in windshield) = Elevation 426.61 Handrail on the Triple Overpass = Elevation 428.40 1.79ft z207 - 12 minutes = .2degrees .2degrees at an elevation 1.39ft above the south knoll, its elevation = 426 (using Drommer plat.) Elevation 426 + 1.39 = 427.39 = shooter rifle barrel elevation, pulling trigger at approx z207. Barrel is approx 1 foot lower than the Overpass handrail. Bullet hits windshield, fragments, slows down to approx (741 x .724 ft per sec) 536ft per sec, deviates downward 2.08inches and strikes JFK's throat.

More precise specs for the weapon. Matching muzzle speed performance More precise specs for the weapon. Matching muzzle speed performance above at 105 (added on edit)133 yards. Disregard the 105yd graph below. https://www.militaryfactory.com/smallarms/detail.asp?smallarms_id=686 Just convert the time into frames, the frames into distance traveled, the limo elevation drop thereafter, and distance left for the deflection and it all points to the Warren Specter inverse SBT.

Adding this to the previous postings and it's pretty easy to figure out how the true "SBT" occurred.

https://www.youtube.com/watch?v=OmvAImRyb3g The downward bullet deflection(after hitting the windshield) of this head-on(non-angled) shot is 4.8degrees. 4.8degrees = 1" drop per every 1ft traveled The speed at which the video bullet traveled, after hitting the windshield, was reduced to approx 72.4% of it's pre-impact velocity. Subsonic specs below: Range is in Yards.

The actual throat wound height off the ground would have been 41.905" - 1.485 1.62 (2.665 2.8 - 1.18) = 40.42" 40.285" Frazier documented the windshield damage at 14.5" below the windshield top. The limo roof was 57" 57" - 14.5" = 42.5" Windshield damage was approx 42.5" - 40.42" 40.285 = 2.08" 2.215" above the throat wound = a slight downward trajectory from approx 315ft 399ft away. Shooter on the TSBD 6th floor west end say hello to your friend in the carpark upon the south knoll. Added on edit: I used the C6-T3 span. It should be the seat incline (2.8") difference.

Distance from C6 to T3 = 67.7mm

.875" below the collar button =

A 2.665" height difference moving between a 7" thick torso = the inverse of Arlen Specter's SBT .

Throat shot = 24.935 + 1.18 + 15.79" = 41.905" above the ground. Throat shot height 41.905" - back shot height 39.24" = 2.665" height difference.