Chris Davidson

And the last elev. adjustment, with no surprise comes from CE884, the BS entry for z161-z166:  

.05ft

Three adjustments:

.425 + .085 + .05 = .56ft = CE560 lead bullet height.

So the 2nd of 3 adjustments by the WC to arrive at a .56 elev (CE560) change gets us to:

.425 + .085 = .51ft

A few posts back, I mentioned how there were a few pieces to getting us the CE560 (.56ft) bullet lead height input.

We already have .425ft of it.

Now that we realize a 1 to 1 ratio is in play, we can apply that to Frazier's entry of "bullet time to impact" (.085 sec) and "limo distance traveled" (1.4ft????)

1 zframe = .0546sec = .0546 vert ft.

Frazier's .085sec / .0546 = 1.5567 zframes and 1.5567 horiz ft traveled.

Frazier's .085 sec = .085 vert elev

If you look at these two entries in the z207 decipher link:

3.27FT/60MIN = .0545 vert ft. per min

1ft vertical/18.3ft horizontal (ElmSt slope) = .0546vertical ft /1ft horizontal

There is one more entry needed to connect the common ratio among them:

1frame/18.3frames = .0546 seconds per frame

Slick how that works.

P.S.  3.276/60 = .0546 exactly

Use this link to help decipher survey z207:

http://educationforum.ipbhost.com/topic/22692-swan-song-math-rules/?do=findComment&comment=330706

The 3.27ft vertical elevation used in CE884 for JFK's height converts to 1deg.

There was a 1.13deg difference between POSITION A and Station 250.0

Converting that difference (in terms of elevation) :

3.27 x 1.13 = 3.695ft

3.695ft - 3.27ft = .425ft difference

If this answer sounds familiar, it should:

10 hours ago, Chris Davidson said:

The three common entries used to complete the feat:

3.27ft

3.13degrees 

10.2ft

The more exact distance would be 10.2351ft

10.2351/3.27 = 3.13

 

 

 

 

 3.13deg - 2 deg = 1.13deg

6 hours ago, Chris Davidson said:

The span of 28.5ft (distance from POSITION A to Station# 250.0) with an elevation change of 1ft equals a 2 degree slope.

This will help(mathematically) in the exacting of the listed .56ft lead bullet height on CE560.

 

The three common entries used to complete the feat:

3.27ft

3.13degrees 

10.2ft

The more exact distance would be 10.2351ft

10.2351/3.27 = 3.13

Just ask for an electronic primer. You obviously haven't a clue. 

So you see, you haven't been ignored, you just don't understand the response.

One more time, pull out your stopwatch boys and girls.

https://drive.google.com/file/d/1CFdpSs8Bt4f-GVJOCOl2wDXdpu-uNjQX/view?usp=sharing

The span of 28.5ft (distance from POSITION A to Station# 250.0) with an elevation change of 1ft equals a 2 degree slope.

This will help(mathematically) in the exacting of the listed .56ft lead bullet height on CE560.

The difference in elevation between POSITION A and elevation 429.7 = 1ft

The actual elevation difference should = 1.557ft.

That is an elevation WORKING difference of .557ft

Where does that difference appear.

Right back to CE560 (upper red box) in the form of the "lead bullet height" listed at .56ft

In a little while, I'll show you how that becomes exactly .56ft using cumulative WC adjustments.

If you haven't figured this out by now, the elevation drop of 28.5ft (from POSITION A to Station# 250.0) should =

28.5/18.3 (3.13degree slope) = 1.557...ft

The distance difference between 28.5/18.3ft is 10.2ft

Robert West indicates this 3.13deg slope extending to Station# 250.0 on the FBI/SS combo plat of Dec63/Feb64.

Added on edit:

He also entered it on the WC final plat of May1964:

3deg8min = 3.13degrees

The thin red line that traverses Elm St. connects 61ft from the TSBD base (snipers nest) and 28.5ft (POSITION A) from Station # 250.0(snipers nest alignment out on Elm St). 

Answer = 10.2ft

This graphic also equals the distance difference between Position A and Station# 268.3 = 

On 2/18/2018 at 4:35 PM, Chris Davidson said:

Where was the 30.86ft split applied to the Position A part of the ballfield:

Sprague designates JFK@ z133 to Station # 299.0, which is where I plotted him also.

I believe we were a slight bit off and JFK actually plots at 299.16 or 1.92 inches difference.

299.16 - 30.86ft = Station 268.3

Station# 268.3 + 10.2ft = Station # 278.5

Position A = Station# 278.5

This can be determined by using the WC data readily available:

z161 = 329.2 - 94.7 = Station C = 234.5

234.5 + 44 = 278.5 = Position A

The WC math-ical mystery tour.

P.S. Position A is not plotted on Robert West's path.

 

 

 

 

 

 

 

 

 

 

Moving backwards some more:

299.16 - 30.86 = 268.3

268.3 - 18.3 (1ft vertical@3.13deg slope) = Station# 250.0 = TSBD Snipers nest parallel street Elevation.

19 hours ago, Chris Davidson said:

I believe the scenario plays out this way:

3.356ft x 12" = 40.272inches

40.272" - 1.5inches = 38.772inches

38.772inches - 5.04inches = 33.732inches

33.732inches + 14cm(5.51inches) = 39.242inches = 3.27ft

 

 

So it's not lost in all of this:

5.04inches (Elev correction)

1.5inches (collar height)

3.54inch difference

On 2/18/2018 at 10:37 AM, David Josephs said:

Who do we suppose put Shaneyfelt, Frasier, Gauthier, Eisenberg, Redlich and the rest to change CE585 and CE884....

 

 

 

Don't know. But the z207/208 shot removal/remedy was being addressed long before CE560 materialized.

Within CE560, they are trying to move this shot by attaching the .56ft lead height = 10.2ft horizontal = z217/218 =  Station# 381.3 = shot #1 on FBI/SS plat of DEC63/FEB64.

While at the same time, showing us that the bullet was fired at approx z207.15 and hit its mark at approx  z208.69

The 2.3ft distance listed on CE884 is the combination of the average speed of the limo (.9ft per frame) + the distance the limo would have traveled from firing of rifle to hitting target (1.4ft).

Specifically:

175/2070 = .0845 / .0546 (1frame/18.3frames) = 1.54frames

The audio indicates z208.69

208.69 - (207 + 1.54) = .15frames

207 + .15 = frame# 207.15 pulled the trigger.

And, to reintroduce the acoustics again for this physical location:

(z313) 144.9 - 139.2 = 5.7 sec x 18.3fps = 104.31 frames

313 - 104.31 =  z208.69

That's a match with the back shot from the previous postings.

Which means, by the time they switched paths, the 162.34ft base distance synced with Shaneyfelt plotted z208.

This, by no coincidence is where we have a splice in the extant zfilm.

1 hour ago, Chris Davidson said:

Credit Tom Purvis via Robert West:

Conversion coming.

 

 

I believe the scenario plays out this way:

3.356ft x 12" = 40.272inches

40.272" - 1.5inches = 38.772inches

38.772inches - 5.04inches = 33.732inches

33.732inches + 14cm(5.51inches) = 39.242inches = 3.27ft

Credit Tom Purvis via Robert West:

Conversion coming.

JFK's shirt collar appears to be 1.5 inches in height.

If anyone knows differently, please feel free to chime in.

https://drive.google.com/file/d/1l1j92AXGJTsr1vP7KPEmhSYmkMr0hzfT/view?usp=sharing

When converted, the difference in elevation from 65.05ft to 64.63ft = .42ft = 5.04 inches.

3.27ft (39.24inches) - 5.04 inches = 34.2 inches = 2.85ft

The difference between 3.27 and 2.85ft = .42ft = elevation change difference in extant survey z207.

On 2/21/2018 at 8:33 AM, Chris Davidson said:

West knew they were up to no good. Probably not all the specifics.

He documented and kept what he could or felt safe with.

 

 

 

This is how crafty the WC was in obtaining their desired goals:

Robert West's survey information for extant z207 lists a right triangle of:  base=162.34ft  height=65.05ft  hypotenuse = 174.88ft

It was determined(don't know by whom- see plat) that 61ft from the TSBD base, along that same extant z207 base measurement, the Elm St. slope of 3.13 degrees began.

The change in elevation would calculate like this:

162.34 - 61= 101.34ft / 18.3ft (1ft Vertical change) = 5.53ft vertical change.

Base to 6th floor window sill = 61.2ft

Rifle end to Window sill = 1.17ft

Total elevation above street = 67.9ft

67.9ft -3.27ft(CE884 -JFK determined back shot elevation) = 64.63ft

Do you see see the difference in vertical elevation?

JFK was shot in the back at physical location extant z207/z208.

On 2/20/2018 at 8:09 AM, David Josephs said:

So Chris... what becomes apparent to me is the arbitrary location for STATION C...

As Shaneyfelt puts it, "The spot where the limo would have turned off Houston onto Elm"...  does this suggested it didn't?

I did this to show that STATION C can lead to either path... despite POSTION A not being on the limo's path and NOT the last place where the mark on the back of the stand-in can be seen... POSITION A is included and critical... z161, which was actually z168 in the final numbering of frames becomes THE spot... but only after May '64... before that it was 168

and the fabrication/alteration of material fact begins....

 

 

David,

I tend to treat StationC in sync relationship to the TSBD.

Two endpoints if you will.

StationC = Station# 234.5

TSBD = Station# 250.0

That is a distance difference of 15.5 ft

They should have advanced a distance of 15.25ft (10" drop) = 15.25ft

18.3 /18 = 1.0166.. - Conversion between determined frame rate and whole frames.

1.01666.. x 15.25 = 15.50ft

Just as 30.86ft was used as a retard and advance concept (shown previously), why not some form of that here.

Arbitrarily set. I agree.

Position A, still working on it.