The Education Forum # Chris Davidson

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• ### Michael Cross

1. Thank you Robert, The PDF version is freely available here: http://pacinlaw.us/pdf/sup/Rulers_of_Evil.php
2. WC ballistic meld of two shots?
3. The accolade is well deserved. Congrats David. Keep up the good work.
4. 166.666/18.3 = 9.107sec 30ft/9.107sec = 3.294ft per sec = Yes, the speed of the limo is very important, as was known by the entity with unlimited resources. I hope you don't truly believe your comment about incompetence related to the WC work. The only people I know of that refer to CE884(both versions) as "junk data" are those that don't understand its intrinsic value. I wish you well with the animation, but I've shown you have a problem with the limo speed and until you realize what's needed to resolve it, my input is complete. I call it "thinking outside the box" P.S. Something to ponder/review: How does this lead back into the initial timing problems you had with the Z/Bell/Wiegman sync.
5. Backtracking to z133: The graphic consists of Sprague/Cutler scaled/layered over the May 1964 WC plat. Look closely(3+00) and you’ll find that Sprague plots z133 at Station# 2+99. CE884 lists z161@Station#3+29.2 329.2 - 299 = 30.2ft. The WC shorted the distance from z161-z166. What happens if you account for that missing distance(z161-5 frames) by retarding those five frames. z133-z156 = 30.2ft 30.2ft/23 frames = 1.313ft per frame x 18.3 = 24.02ft per sec/1.47 = 16.34mph Referring back to your animation for(z161-z185) which gives us: 9.6 + 11.1 = 20.7/2 = 10.35mph average 16.34 - 10.35 = 5.99mph 10.35 + 2.24 + 3.74 = 16.33mph Constant: 2.24mph = The limo speed from CE884 z161-z166 (Official version) 3.74mph = The limo speed from CE884 z168-z171(WC final May 1964)
6. Next, let’s use your z166-z185 = 9.9 + 11.1 = 21/2 = 10.5 average + 5.98 constant (explanation coming) = 16.48mph 19.2ft/19frames = 1.01 x 18.3 = 18.492 / 1.47 = 12.58mph 12.58 x 1.311(ratio explanation coming)= 16.49mph The follow up post will backtrack this to z133.
7. O.K. Let’s use your animation for(z161-z185) which gives us: 9.6 + 11.1 = 20.7/2 = 10.35mph average This time, using the “white in color-official CE884-z166-z185” inset = 19.2ft/19frames = 1.01 x 18.3 = 18.492 / 1.47 = 12.58mph 12.58 -10.35 = 2.23mph CE884 z161-z166 = 5 frames 18.3/5 = 3.66 x .9ft traveled = 3.294ft per sec / 1.47 = 2.24mph
8. Generally speaking, you are following along very well. The beauty of your animation(among other aspects) is the instantaneous speeds created. This creates an "apples to apples" comparison with the WC math when the proper ratio's are applied. The graphic above was to illustrate the relevant CE884 data in terms of a true/r limo speed. Let's adjust your animation average(graphic below) speed between z136-z149 = 8.6 + 9mph = 17.6/2 = 8.8mph average with one such ratio. 8.8 mph x 1.6666(explanation to come) = 14.66mph If you look at my plat measurements for this span you'll see I arrived(distances provided) with a limo speed of 14.65mph. This in fact tells me that the ratio introduced and applied to your instantaneous speed is a match. If you follow, I'll move on.
9. Let me move it totally forward for Z133-Z486 = 353 frames. The question I would ask (since we have been talking about the Wiegman film) is: What was the approx missing time from Groden's version to Von Pein's version? I'll answer that for you: 353/24 = 14.708sec 14.708 sec x 18.3fps = 269.16 frames 353 - 269.16 = 83.84 frames rounded = 84 frames 84/24fps = 3.5 seconds That's the reason why Wiegman's film(what we have been privy to) was missing approx 3.5 seconds.
10. Mark, When a 48fps slo-mo has 1/2 the frames removed, it gives you a variation of 24fps.
11. Ian, That would be a legitimate concern. Let me correct it slightly and say 48fps in slo-mo.
12. Working backwards some more, let's move Myers back to Z133: 246-133 = 113 113/24 = 4.7sec (close enough, you get the picture) 113/18.3 = 6.174 6.174 - 4.7 = 1.474sec That's why I said pretend in adding the time to the Bell gap, way after the fact. Does anyone see the difference in making this sync occur? Think in terms of frame rates if you missed it.
13. Here is a minor clip from Groden after de-interlacing the VOB file. It is now in the 2:3 pulldown stage. (See info above) There are 994 total frames in this version. 994 x .8 = 795.2 frames It is 33.13 seconds long. 795.2/33.13sec = 24fps.
14. This might help out with the previous quote. The conversion of the original Wiegman film from 24 to 30 fps involved one or the other process. The second process not included in the graphic involved adding one repeat frame with four progressive ones. The end result is the same in terms of total frames created. The total frame count for the Wiegman 36.5sec version = 1096 frames (see graphic-red box). If you want to convert this back to total frames for a 24fps progressive movie, multiply total frames by (24/30) = .8 1096 x .8 = 876.8 total progressive frames 876.8/ 36.5sec = 24.02 fps
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