Chris Davidson Posted August 22, 2019 Author Share Posted August 22, 2019 The inch designed building blocks the WC used were: .875 + 2.665 = 3.54 + 10 + 39.24 = 52.78" = JFK's stated/testimony head height above the street while seated in the limo. Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 22, 2019 Author Share Posted August 22, 2019 1 hour ago, Chris Davidson said: Before the incline, the back hole was .75" above the throat hole. After the incline, the back hole is below the throat hole by .75 - 1.18 = -.43" Did you happen to run .43" through a run/rise calc at 7"? Then deduct 3.13° for the reverse Elm St slope. 3.52° - 3.13° = .39° = 0deg 23.4minutes And, match it back to a CE884 frame # from the bridge handrail(overpass). z210-z222 = 2/12 = .1666min per frame 1.4min/ .1666min per frame = 8.4 frames z210 + 8.4 frames = z218.4 Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 22, 2019 Author Share Posted August 22, 2019 8 hours ago, Chris Davidson said: Button the shirt, along with what's in the red square. Link to comment Share on other sites More sharing options...
Paul Bacon Posted August 23, 2019 Share Posted August 23, 2019 12 hours ago, Chris Davidson said: Button the shirt, along with what's in the red square. If only Arlen Specter had .gif's available to him... Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 24, 2019 Author Share Posted August 24, 2019 On 8/22/2019 at 1:53 PM, Chris Davidson said: The inch designed building blocks the WC used were: .875 + 2.665 = 3.54 + 10 + 39.24 = 52.78" = JFK's stated/testimony head height above the street while seated in the limo. Link to comment Share on other sites More sharing options...
Ray Mitcham Posted August 24, 2019 Share Posted August 24, 2019 On 8/23/2019 at 12:54 AM, Chris Davidson said: Button the shirt, along with what's in the red square. Chris, the deniers will just say "the front of the shirt must have bunched up".😁 Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 27, 2019 Author Share Posted August 27, 2019 Ray, That's fine. I'll just continue on, to where a/the back shot came from. Mr. SIMMONS. Yes; we did. We placed three targets, which were head and shoulder silhouettes, at distances of 175 feet, 240 feet, and 265 feet, and these distances are slant ranges from the window ledge of a tower which is about 30 feet high. We used three firers in an attempt to obtain hits on all three targets within as short a time interval as possible. Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 Next, refer back to these two posts: http://educationforum.ipbhost.com/topic/22692-swan-song-math-rules/?do=findComment&comment=405207 http://educationforum.ipbhost.com/topic/22692-swan-song-math-rules/?do=findComment&comment=390993 1.625" - 1.18" = .445" back hole higher than throat hole. Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 On 8/27/2019 at 4:14 PM, Chris Davidson said: Mr. SIMMONS. Yes; we did. We placed three targets, which were head and shoulder silhouettes, at distances of 175 feet, 240 feet, and 265 feet, and these distances are slant ranges from the window ledge of a tower which is about 30 feet high. We used three firers in an attempt to obtain hits on all three targets within as short a time interval as possible. Height and angle. Distance next. Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 1" = 10ft Base measurement match: See previous post. The LOS from elev. 423.07 = Shot #1 labeled on the SS/FBI Dec-1963 plat. Richard Sprague used z226 back to the Dal-Tex building as his LOS, I just shortened it to elev 423.07(approx z218) and ran his LOS back to the Dal-Tex. It intersects approx 30ft from the Dal-Tex corner. Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 1 hour ago, Chris Davidson said: Height and angle. Distance next. I arrived at the 30ft height this way: Elev. of Dal-Tex building base = 430.8ft (430.2 + .3 (SniperNest to TSBD Corner) + .3 (TSBD Corner to Dal-Tex) Drommer converted back to West: 430.2 - 100.4 = 329.8 + 161.1 = 490.9 2nd floor window sill = 20ft = (approx height of the TSBD 2nd floor) Elev 450.8 - 423.07(shot#1-SS/FBI Dec-1963 plat) = 27.73ft - 3.27ft(CE884 elev difference) = 24.46ft. 30 - 24.46 = 5.54ft = Rifle barrel end above 2nd floor window sill. Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 5.54ft = Rifle barrel end above 2nd floor window sill. https://drive.google.com/file/d/1lLlmgPGz97j-x-FoxxtWD3mfSatDPywA/view?usp=sharing Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 If you missed the laser dot, I put a red box around it. The Google view should help with orientation. Does that look close to 5.54ft above the 2nd floor window ledge? Link to comment Share on other sites More sharing options...
Chris Davidson Posted August 29, 2019 Author Share Posted August 29, 2019 21 minutes ago, Chris Davidson said: 5.54ft = Rifle barrel end above 2nd floor window sill. https://drive.google.com/file/d/1lLlmgPGz97j-x-FoxxtWD3mfSatDPywA/view?usp=sharing Were there prospective suspects that fit the location? Link to comment Share on other sites More sharing options...
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